in triangle abc right angled at B if 10 is equal to one by root 3 find the value of Sin A cos C + cos a sin c
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Tan A = P/B= 1/√3
by pytagorous theorem
H^2= 1^2+ √3^2
= 1 +3
= 4
H= √4. =2
sin A cos C + cos A sin C
1/2×1/2+√3/2×√3/2
1/4+3/4
4/4
=1
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by pytagorous theorem
H^2= 1^2+ √3^2
= 1 +3
= 4
H= √4. =2
sin A cos C + cos A sin C
1/2×1/2+√3/2×√3/2
1/4+3/4
4/4
=1
I HOPE IT'S HELP YOU
MAKE ME BRAINLIEST
Answered by
1
YOUR ANSWER IS 4
Tan A = root 3
tan A = opposite side / adjacent side
= root 3 / 1
By pythagoras theorem
AC square = AB square + BC square
= 1 square + root 3 square
= 1 + 3
= 4
= sin A . cos A + cos A . sin C
= root 3 /2 × root 3/2 + 1/2+1/2
= 3/4 + 1/4
= 3+1/4
= 4/4
= 1
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