Math, asked by DanielShadap, 1 year ago

in triangle ABC, right-angled at B, if AB=5, BC=12 and AC=13, find all the six trigonometric ratios of angle A​

Answers

Answered by sabhya18
19

sin 12/13

cos 5/13

tan 12/5

cosec 13/12

sec 13/5

cot 5/12

ans...

Answered by erinna
13

The trigonometric ratios of angle A are \sin A=\dfrac{12}{13},\cos A=\dfrac{5}{13},\tan A=\dfrac{12}{5}, \csc A=\dfrac{13}{12}, \sec A=\dfrac{13}{5} and \cot A=\dfrac{5}{12}

Step-by-step explanation:

Given information: In triangle ABC, right-angled at B, if AB=5, BC=12 and AC=13.

We need to find the all the six trigonometric ratios of angle A​.

Hypotenuse of triangle ABC : AC = 13

For angle A,

Opposite side : BC=12

Adjacent side : AB=5

\sin A=\dfrac{opposite}{hypotenuse}=\dfrac{12}{13}

\cos A=\dfrac{adjacent}{hypotenuse}=\dfrac{5}{13}

\tan A=\dfrac{opposite}{adjacent}=\dfrac{12}{5}

\csc A=\dfrac{hypotenuse}{opposite}=\dfrac{13}{12}

\sec A=\dfrac{hypotenuse}{adjacent}=\dfrac{13}{5}

\cot A=\dfrac{adjacent}{opposite}=\dfrac{5}{12}

Therefore, the trigonometric ratios of angle A are \sin A=\dfrac{12}{13},\cos A=\dfrac{5}{13},\tan A=\dfrac{12}{5}, \csc A=\dfrac{13}{12}, \sec A=\dfrac{13}{5} and \cot A=\dfrac{5}{12}.

#Learn more

In a right triangle abc right angled at b if sin a =3/5 find all six trigonometric ratios​.

https://brainly.in/question/9835683

Similar questions