In triangle ABC,right angled at B,side AB=40 cm and BC =9cm . find the value of sin A,cosA, and tan A
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Answer:
Sin A = 9/AC
Cos A = 40/AC
Tan A = 0.225
Step-by-step explanation:
Sin = opposite side
hypotenuse
Cos= adjacent side / hypotenuse
tan = opposite side / adjascent side
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