In triangle ABC right angled at C, if 3 cot A = 4, find the value of sin B.
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3 cot A = 4
cot A = 4/3 = B/P
B = 4 , P = 3
Pythagoras theorem
(p)² + (b)² = (h)²
(3)² + (4)² = h²
9 + 16 = h²
25 = h²
√25 = h
5 = h
sin B = P/H = 3/5
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