Question

In triangle ABC, right angled at QPR+PQ =25cm and PQ=5cm and PQ 5cm.Dtermined the value of sin p, cos p and tan p​

Answer 1

$\sf \pmb{Answer :}$

Given PR + QR = 25 , PQ = 5

PR be x.  and QR = 25 - x 

Pythagoras theorem ,PR2 = PQ2 + QR2

x2 = (5)2 + (25 - x)2

x2 = 25 + 625 + x2 - 50x

50x = 650

x = 13

 

 PR = 13 cm

QR = (25 - 13) cm = 12 cm

sin P = QR/PR = 12/13

cos P = PQ/PR = 5/13

tan P = QR/PQ = 12/5

Answer 2

Answer:

Given PR + QR = 25 , PQ = 5

PR be x. and QR = 25 - x

Pythagoras theorem ,PR2 = PQ2 + QR2

x2 = (5)2 + (25 - x)2

x2 = 25 + 625 + x2 - 50x

50x = 650

x = 13

PR = 13 cm

QR = (25 - 13) cm = 12 cm

sin P = QR/PR = 12/13

cos P = PQ/PR = 5/13

tan P = QR/PQ = 12/5