Question

In triangle ABC, right anglesd at B, AC= 20 cm and tan ∠ACb=3/4; calculate the measures of aB and BC.​

Answer 1

《✭Answer✭》

tan ∠ACB=$\sf \frac{3}{4}$➡

$\sf\frac{AB}{Bc}=\frac {3}{4}$

Let AB=3x cm,

Therfore, BC=4x cm

$\sf \: AB^2+BC^2=AC^2$

[Using pythagoras theorem]

$\sf \rightarrow{(3x)}^{2} + {(4x)}^{2} = {(20x)}^{2}$

$\sf \rightarrow {25x}^{2} = 400 \\ \\ \sf \implies \: x = 4$

Therfore;

AB= 3x=3×4=12 cm

BC=4x=4×4=16 cm

Hope it helps you...

Answer 2

Answer:

Ab = 12 ,bc = 16 cm

Step-by-step explanation:

@mrmysteryy