Question

In triangle ABC, Seg AP is a median if
Bc =18 AB²+AC²=260 Find
AP?
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Answer 1

Answer:

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Step-by-step explanation:

given- AB²+AC²=260

BC=18

AP is the median

Therefore,BP=CP

To find- Seg AP

solution- AP is the median....(given)

therefore,BP=1/2×BC

=1/2×18

= 9

By apollonius theorem,

AB²+AC²=2AP²+2BP²

260=2AP²+2×(9)²

2AP²=260-162

2AP²=98

AP²=49

AP=7

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