Question

In triangle ABC, seg BD bisects angle ABC. If AB=x, BC=x+5,AD=x-2, DC=x+2,then find value of x

Answer 1

Answer:

x=10

Step-by-step explanation:

We are given a ΔABC

Segment BD bisects ∠ABC

Refer the attached image

Definition of an angle bisector of triangle :  An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle.

Thus ,

$\frac{AD}{CD} =\frac{AB}{BC}$

$\frac{x-2}{x+2} =\frac{x}{x+5}$

$(x-2)*(x+5)=(x+2)*x$

$x^{2}-2x+5x-10 =x^{2}+2x$

$3x-10=2x$

$x=10$

Thus the value of x is 10

Answer 2

Answer:

✔️✔️Answer..

x=10...

I hope it helps...