Question

in triangle ABC seg mn parallel side AC. seg MN divides triangle ABC into two parts equal in area. determine am/mb

Answer 1

ABC ~ MNB
since AC parallel AN
therefore AM/BM =BN/CN=MN/AC
AB is divided in M
therefore AM=BM


HOPE IT HELPS

Answer 2

Solution :-

Answer:

√2

Step-by-step explanation:

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2× (area of ΔAMN )= area of ΔABC

so

AM/ MB =√area of ABC / √area of AMN

AM/MB= √1/2

AM /MB = √2

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@GauravSaxena01