Question

In triangle ABC seg PQ parallel side AB,CP = 8, AP= 4,BQ= 6 find CQ=?
plz solve step by step​

Answer 1

Answer:

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Answer 2

Answer:

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PQ∥AC,AP=4cm,PB=6cm and BC=8cm

∠BQP=∠BCA … [because alternate angles are equal]

Also, ∠B=∠B … [common for both the triangles]

Therefore, △ABC∼△BPQ

Then, BQ/BC=BP/AB=PQ/AC

BQ/BC=6/(6+4)=PQ/AC

BQ/BC=6/10=PQ/AC

BQ/8=6/10=PQ/AC … [because BC=8cm given]

Now, BQ/8=6/10

BQ=(6/10)×8

BQ=48/10

BQ=4.8cm

Also, CQ=BC−BQ

CQ=(8−4.8)cm

CQ=3.2cm

Therefore, CQ=3.2cm and BQ=4.8cm.

Step-by-step explanation:

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