in triangle abc similar triangle pqr and area of triangle ABC equal to 121 CM square area of triangle pqr 81 CM square. BC equal to 3.3 cm find the value of QR
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A(∆ABC). (BC)²
-------------- = ----------
A(∆PQR). (QR)²
121. ( 3.3)²
----= -----------
81. QR²
=>√121/√81= 3.3/QR
=>11/9=3.3/QR
=>QR= (3.3×9)/11= 0.3×9= 2.7 cm will be the answer
-------------- = ----------
A(∆PQR). (QR)²
121. ( 3.3)²
----= -----------
81. QR²
=>√121/√81= 3.3/QR
=>11/9=3.3/QR
=>QR= (3.3×9)/11= 0.3×9= 2.7 cm will be the answer
satishyadav0729:
Thank u bro
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