Question

in triangle ABC the bisector of angle b and angle c intersect at a point o. prove that angle BOC = 90 + 1/2angle c​

Answer 1

A+B+C=180

OBC+OCB+BOC=180

B/2+C/2+BOC=180

(B+C)/2+BOC=180

(180-A)/2+BOC=180

90-A/2+BOC=180.

BOC=90+A/2

4.1

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