Question

In triangle ABC, the external bisectors
of the angles B and C meet at
the point O. If angleA=70°, then the
measure of angle BOC is :
( 55°
(2) 75º
(3) 60° (4) 50°​

Answer 1

angle A = 70° ( given )

angle BOC = ?

then, by using theorem we can say that

angle BOC = 90°- 1/2 of angle A

BOC = 90° - 1/2 × 70°

BOC = 90° - 70°/2

BOC = 90°- 35°

BOC = 55°