Question

in triangle ABC the measure of angle A is 40 degree less than the measure of angle of angle B and 50 degree less than that of angle C find the measure of /A​

Answer 1

Answer:

Let Angle A be X

let Angle B be X +40

Let Angle C be X + 50

ATQ

Angle A + Angle B + Angle C = 180° ( Angle sum property of triangle)

X + X +40 + X + 50 = 180°

3X + 90 = 180°

3X = 180 - 90

3X = 90

X = 90/3

X = 30

Therefore, Angle B = X+ 40 = 70

and Angle C= X+50 = 80