IN triangle ABC,the medians BP and CQ are perpendicular to each other and intersect at R if BP=8 cm and CQ= 12cm ,find the area of triangle ABC
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Given: Medians BP and CQ are perpendicular to each other, BP= 8cm , CQ = 12cm.
To find: The area of triangle ABC?
Solution:
- Let the intersection point of the median be Z
- Now from the triangle we can understand that Z is the centroid of the triangle ABC.
- So, since Z is the centroid, we get:
CZ = 2QZ
8/2 = QZ
QZ = 4 cm
- So, area ∆PBC = 1/2 * 8 * 8 = 32cm².
- So now as we know that the median divides the triangle into two equal areas, so:
area ∆ABC = area ∆BPC x 2
= 2 x 32 cm²
= 64 cm²
Answer:
So, the area of triangle ABC is 64 cm².
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hope this can you a lot mark .e brainliest
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