in triangle def altitude ds bisects the side ef, prove that def is an isosceles triangle
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consider the triangles DES and DFS
ES=FS ( bisector )
angle(DSE)=angle(DSF)=90° (altitude)
DS=DS( common side )
therefore by SAS rule triangle DES and DFS are congruent
we can therefore say sides DE=DF implies DEF is an isoceles triangle
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