Math, asked by saikeerthana19730, 4 months ago

in triangle JOY, angle JOY=90°, then the value of cos (J+Y) =?

Answers

Answered by Sparklez

0

Step-by-step explanation:

cosJcosY-sinJsinY

JO/JY x OY/JY- JO/JY x OY/JY=0

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