in triangle opq, right angled at p,op=7cm and oq-pq=1cm detemine the values of sin q and cos q
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9
Given Op=7cm
given Oq-pq=1 cm
let oq be x and pq be x-1
as per Pythagorean theorem √(x^2-(x-1)^2)=7cm
after solving we get x=25
therefore oq=25cm
pq=24cm
therefore sin q=7/25=p/h
cos q=24/25=b/h
hope I have helped you!
given Oq-pq=1 cm
let oq be x and pq be x-1
as per Pythagorean theorem √(x^2-(x-1)^2)=7cm
after solving we get x=25
therefore oq=25cm
pq=24cm
therefore sin q=7/25=p/h
cos q=24/25=b/h
hope I have helped you!
Answered by
22
I hope it proves to be helpful for you.
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