Question

In triangle par, s is a point on qr. Show that pq+qr+rp>2ps

Answer 1

Answer:

Step-by-step explanation:

AB is a 6 m high pole and CD is a ladder inclined at an angle of 60° to the horizontal

and reaches up to a point D of pole. If AD = 2.54 m, find the length of the ladder. (use

3

= 1.73)

Answer 2

Answer:

suppose the longer of the two sides PQ and PR  is PQ

PS must be shorter than or equal to PQ. (It's only equal if S and Q are the same point.) 

It is a rule that the sum of any two sides of a triangle must be greater than the third side. So we also know that PR + QR > PQ 

Since PR + QR > PQ 

We know PQ + PR + QR > 2PQ 

(just added PQ to both sides) 

And since PQ >= PS, 

We know 2PQ >= 2PS 

(multipled both sides by 2) 

From those two (PQ + PR + QR > 2PQ, 2PQ >= 2PS), we know: 

PQ + PR + QR > 2PS

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