Question

in triangle PQE,QR=PQ, angle Q=70degree then angle R is ​

Answer 1

Step-by-step explanation:

180=q+r+p. p=r=x

q=180-p+r

70=180-2x

2x=110

x=55

r =55°

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Answer 2

Answer:

NOTE: IT IS ΔPQR, NOT PQE.

Let's draw the figure (I used ms paint for the figure)

Now, QR=PQ, thus ΔPQR is an isosceles triangle.

In an isosceles triangle, the base angles are always equal. thus, ∠R=∠P.

Now, we know that sum of angles of a triangle are equal. Thus,

∠P+∠Q+∠R=180°

∠R+∠R+70°=180° [ ∠R=∠P.]

2∠R=180-70

∠R=110÷2

∠R=55°

HOPE THIS HELPS :D