In triangle PQR a line drawn parallel to seg QR intersects side PQ in A and side PR in B . if PA=15 , PB=5 , BR=3 find AQ
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PB + BR = PR
PR = 10 cm
PA/PQ = 5/12.5
= 2/5
= PB/PQ =4/10
= 2/5
as PA/PQ = PB/ PQ by basic proportionality theorem they are parallel
Answered by
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Answer:
Step-by-step explanation:
GIVEN :In triangle PQR
AB||QR
Let QA=x
THEREFORE BY BASIC PROPORTIONALITY THEOREM
PA/QA=PB/RB
15/x=5/3
Cross multiply
5x=45
x=45/5
x=9
THEREFORE AQ=9 Answer
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