Math, asked by adityawakkar05, 6 months ago

In triangle PQR, angle PQR = 90°. Seg QS perpendicular to Seg PR, QS=15, PS= 9, find SR.

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Answered by rajunaga110

1

Answer:

triangles qsp~rsq

so rs/sq=sq/sp

rs*sp=sq^2

rs*9=15*15

rs=5*5=25

rs=25

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