Question

in triangle pqr, angle q=90, find, pr, if pq=8cm and qr=6cm

Answer 1

$since \: angle \: q = 90 \: degree \\ triangle \: pqr \: is \: a \: right \: angled \: triangle \\ therefore \\ by \: pythagoras \: theorem \\ {pr}^{2} = {pq}^{2} + {qr}^{2} \\ {pr}^{2} = {8}^{2} + {6}^{2} \\ {pr} = 64 + 36 \\ pr = \sqrt{64 + 36} \\ pr = \sqrt{100} \\ pr = 10cm$

Answer 2

PQR is right angle triangle

where hight pq = 8 cm and base qr = 6 cm

so , by pythagoreous theorem

(hyp)²= (Height)²+(Base)²

(hyp)²= 8²+6²

=64+36=100

hence Hyp= pr= 10