Question

in triangle PQR ,angle Q =90.if cot p =40/9 then find 1) length of PR 2) value of sec R 3)value of sin P​

Answer 1

Answer:

PR

2

=PQ

2

+QR

2

⇒(5)

2

=PQ

2

+(4)

2

⇒(5)

2

−(4)

2

=PQ

2

⇒PQ

2

=25−16

⇒PQ

2

=9

⇒PQ=

9

⇒PQ=3

tanR=

QR

PQ

=

4

3

.