In triangle PQR angle Q = angle R. If PQ=6cm and QR= 9cm, than find the perimeter of triangle PQR
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9+6+6=21cm
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Answer:
since angle P= angle R
therefore PQ= PR(sides opposite to equal angles)
therefore in ∆PQR,
PQ=6cm , QR=9cm,& PR=6cm
thus , perimeter of ∆PQR= PQ+QR+PR
=6+9+6cm
21cm
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