Question

in triangle pqr ,angle rqp is 35 degree and pq is equal to pr. what will be the value of qpr (a. 85 b.90 c.105 d.110 ) plz reply as fast
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Answer 1

Step-by-step explanation:

add angle 35 because angle oppo.to equal side are equal

35+35+x=180(angle sum property of triangle)

x=180-70

x=110

Answer 2

Given: In triangle PQR, $\[\angle RQP = {35^ \circ },PQ = PR\]$.

To find: the measure of $\[\angle QPR\]$.

Solution:

Draw the required figure.

Observe that from the question,

$PQ=PR$

$\[ \Rightarrow \Delta PQR\]$ is an isoscles triangle.

$\[\begin{array}{l} \Rightarrow \angle PRQ = \angle PQR\\ \Rightarrow \angle PRQ = {35^ \circ }\end{array}\]$

Find the measure of $\[\angle QPR\]$.

$\[\angle QPR + \angle PRQ + \angle PQR = {180^ \circ }\]$ {sum of angles in a triangle is 180 degrees]

$\[\begin{array}{l} \Rightarrow \angle QPR + {35^ \circ } + {35^ \circ } = {180^ \circ }\\ \Rightarrow \angle QPR + {70^ \circ } = {180^ \circ }\\ \Rightarrow \angle QPR = {180^ \circ } - {70^ \circ }\\ \Rightarrow \angle QPR = {110^ \circ }\end{array}\]$

Hence, the measure of the $\[\angle QPR\]$ is $\[{110^ \circ }\]$.