Question

In triangle PQR, angleQ=90degree ,PQ=8cm and PR=10cm
Find:
1)SinP
2)cosP
3)tanR
4)sinR+secR​

Answer 1

Step-by-step explanation:

PQ = 8cm PR = 10cm

By Pythagoras theorem

QR=6cm

sin P = QR/PR = 6/10= 3/5

cos P = PQ/PR = 8/10 = 4/5

tan R = PQ/QR = 8/6 = 4/3

sin R + sec R = 8/10 + 10/6 =.....

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