Math, asked by khokharakggmailcom, 11 months ago

in triangle PQR, MN // QR such that PM:Q M = 2:3 the ratio of the areas of triangle PQR and quadrilateral QRNM is

Answers

Answered by zagreb
42

Here in ΔPQR, MN || QR

Hence

<PMN = <PQR ( Corresponding angles)

<PNM = <PRQ (Corresponding angles)

So by AA ΔPQR ~ ΔPMN

Hence

 \frac{Area of triangle PMN}{Area of triangle PQR}=(\frac{PM}{PQ})^{2}  =(\frac{2}{5})^2=\frac{4}{25}

So let area of ΔPMN = 4x

So area of ΔPQR = 25x

Hence area of quadrilateral QRNM = 25x - 4x = 21x

So

 \frac{Area of triangle PQR}{Area of quadrilateral QRNM}=\frac{25x}{21x}

 \frac{Area of triangle PQR}{Area of quadrilateral QRNM}=\frac{25}{21}

The ratio of the areas of triangle PQR and quadrilateral QRNM is 25 : 21

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Answered by prachikalantri
2

Here in ΔPQR, MN || QR

Hence

<PMN = <PQR ( Corresponding angles)

<PNM = <PRQ (Corresponding angles)

So by AA ΔPQR ~ ΔPMN

Hence

\frac{Area of triangle PMN}{Area of triangle PQR}=(\frac{PM}{PQ})^2 =(\frac{2}{5} )^2=\frac{4}{25}

So let area of ΔPMN = 4x

So area of ΔPQR= 25x

Hence area of quadrilateral QRNM = 25x - 4x = 21x

So

\frac{Area of triangle PQR}{Area of triangle QRNM}=\frac{25x}{21x}

\frac{Area of triangle PQR}{Area of triangle QRNM}=\frac{25}{21}

The ratio of the areas of triangle PQR and quadrilateral QRNM is 25 : 21

#SPJ2

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