In triangle PQR,PD perpendicular to QR such that D lies on QR . if PQ =a ,PR = b ,QD= c and DR =d ,prove that (a+b) (a-b)=(c+d) (c-d) ???
Answers
Answered by
8
HEYA!
HERE IS THE ANSWER FOR YOUR QUESTION :.
PD2 = PQ2 – QC2 = PR2 – DR2
PQ2 – QC2 = PR2 – DR2
a2 – c2 = b2 – d2
a2 – b2 = c2 – d2
(a – b)(a + b) = (c – d)(c + d)
I HOPE THIS WILL HELP YOU!
HERE IS THE ANSWER FOR YOUR QUESTION :.
PD2 = PQ2 – QC2 = PR2 – DR2
PQ2 – QC2 = PR2 – DR2
a2 – c2 = b2 – d2
a2 – b2 = c2 – d2
(a – b)(a + b) = (c – d)(c + d)
I HOPE THIS WILL HELP YOU!
divyansh4385:
thanks bhai aaaj tune pitne se bcha liya
thanku bhai
Answered by
4
Answer:
Step-by-step explanation:
Attachments:
Similar questions