the sum of sqares of two conseculious even no is 340. find the no
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HEYA!!
YOUR SOLUTION IS IN THE ATTACHMENT.
#KEVIN
HOPE IT HELPS YOU ☺
WE can't take - 14 as it is negative..
YOUR SOLUTION IS IN THE ATTACHMENT.
#KEVIN
HOPE IT HELPS YOU ☺
WE can't take - 14 as it is negative..
Attachments:
Answered by
3
Let the consecutive even numbers be x and x + 2.
Given that the sum of squares of two consecutive even numbers = 340.
x^2 + (x + 2)^2 = 240
x^2 + x^2 + 4 + 4x = 340
2x^2 + 4 + 4x = 340
2x^2 + 4x = 340 - 4
2x^2 + 4x = 336
2x^2 + 4x - 336 = 0
2(x^2 + 2x - 168) = 0
x^2 + 2x - 168 = 0
x^2 - 12x + 14x - 168 = 0
x(x - 12) + 14(x - 12) = 0
(x - 12) = 0 (or) (x + 14) = 0
x = 12 (or) x = -14.
Therefore the two integers are 12 and 14.
Hope this helps!
Given that the sum of squares of two consecutive even numbers = 340.
x^2 + (x + 2)^2 = 240
x^2 + x^2 + 4 + 4x = 340
2x^2 + 4 + 4x = 340
2x^2 + 4x = 340 - 4
2x^2 + 4x = 336
2x^2 + 4x - 336 = 0
2(x^2 + 2x - 168) = 0
x^2 + 2x - 168 = 0
x^2 - 12x + 14x - 168 = 0
x(x - 12) + 14(x - 12) = 0
(x - 12) = 0 (or) (x + 14) = 0
x = 12 (or) x = -14.
Therefore the two integers are 12 and 14.
Hope this helps!
Anonymous:
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