In triangle PQR PQ= PR angleQ= 65 degrree then find angle p
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Answered by
50
by using the theorem,If two sides of a triangle are equal then the opposite angles to the sides are equal.
⇒if PQ=PR then ∠Q=∠R
in triangle PQR,
⇒∠P+∠Q+∠R=180°
⇒∠P+∠Q+∠Q=180° (∵∠Q=∠R)
⇒∠P+65°+65°=180°
⇒∠P+130°=180°
⇒∠P=180°-130°
⇒∠P=50°
⇒if PQ=PR then ∠Q=∠R
in triangle PQR,
⇒∠P+∠Q+∠R=180°
⇒∠P+∠Q+∠Q=180° (∵∠Q=∠R)
⇒∠P+65°+65°=180°
⇒∠P+130°=180°
⇒∠P=180°-130°
⇒∠P=50°
Answered by
10
Answer:
50°
Step-by-step explanation:
We are given that PQ=PR
Theorem: If two sides of a triangle are equal then the opposite angles to the sides are equal.
PQ=PR
SO,∠Q=∠R
In Δ PQR,
⇒∠P+∠Q+∠R=180°(Angle sum property of triangle)
⇒∠P+∠Q+∠Q=180° (∵∠Q=∠R)
⇒∠P+65°+65°=180°
⇒∠P+130°=180°
⇒∠P=180°-130°
⇒∠P=50°
Hence The angle p is 50°
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