In triangle PQR, PQ = PR, QN = RM. Prove that
angle QPM = angle RPN.
Answers
Given :- In triangle PQR, PQ = PR, QN = RM.
To Prove :- ∠QPM = ∠RPN .
Solution :-
In ∆PQR, we have,
→ PQ = PR .
so,
→ ∠PQR = ∠PRQ { Angle opposite to equal sides are equal .}
then,
→ ∠PQM = ∠PRN ------------ Eqn.(1)
now,
→ QN = RM (given)
→ QM + MN = RN + NM
→ QM = RN -------------- Eqn.(2)
now, in ∆PQM and ∆PRN we have,
→ PQ = PR { given }
→ ∠PQM = ∠PRN { from Eqn.(1) }
→ QM = RN { from Eqn.(2) }
therefore,
→ ∆PQM ≅ ∆PRN { By SAS congruence rule. }
hence,
→ ∠QPM = ∠RPN { By CPCT .} (Proved)
Learn more :-
in triangle ABC seg DE parallel side BC. If 2 area of triangle ADE = area of quadrilateral DBCE find AB : AD show that B...
https://brainly.in/question/15942930
2) In ∆ABC seg MN || side AC, seg MN divides ∆ABC into two parts of equal area. Determine the value of AM / AB
https://brainly.in/question/37634605