Question

. In triangle PQR, PR = 10 cm, QR = 4 cm and PL = 6 cm.
P.
1
6cm
M
1
10cm
L
Q
R
4cm
(a) Find the area of the APQR.
DL and BM are the
(b) Find QM.​

Answer 1

Area of Δ PQR = 12 cm²

Step-by-step explanation:

PR = 10 cm

QR = 4 cm

PL = 6 cm

LR² = PR² - PL²

=> LR² = 10² - 6²

=> LR = 8

Area of Δ PLR = (1/2) & PL * LR = (1/2) * 6 * 8 = 24 cm²

QR = 4 cm

LQ = LR - QR = 8 - 4 = 4 cm

Area of Δ PLQ = (1/2) & PL * LQ = (1/2) * 6 * 4 = 12 cm²

Area of Δ PQR = Area of Δ PLR  - Area of Δ PLQ  = 24 - 12 =12 cm²

Area of Δ PQR = 8 cm²

Area of Δ PQR =  (1/2)* PR * QM  = (1/2) * 10 * QM = 12

=> QM = 2.4 cm

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