In triangle pqr , qr=7.5cm, angles qpr=110° and pqr+pr=8.3cm construct the triangle pqr and draw its circumcircle
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We follow these steps to form our triangle PQR : But here we can form if given angle is ∠PQR = 110°
Step 1 : Draw a line QR = 7.6 cm
Step 2 : With the help of protector form 110° at point " Q " , As : ∠ RQX = 110°
Step 3 : Take radius of 8.3 cm and center " Q " draw an arc that intersect our line QX at " Y " .
Step 4 : Join RY .
Step 5 : Now take radius more than half of RY and cneter " R " and " Y " draw two arc from both points on both side of line RY , and these arcs intersect at " A " and " B " .
Step 6 : Join line AB and that intersect line QY at " P " .
This is our required triangle PQR .
now to draw its circumcircle draw medians and for that bisect each and every side of the triangle and when median intersects we get a centroid.
measuring the point of centroid to any part of the triangle is radius and draw a cicle therefore it will be the required circumcircle
We follow these steps to form our triangle PQR : But here we can form if given angle is ∠PQR = 110°
Step 1 : Draw a line QR = 7.6 cm
Step 2 : With the help of protector form 110° at point " Q " , As : ∠ RQX = 110°
Step 3 : Take radius of 8.3 cm and center " Q " draw an arc that intersect our line QX at " Y " .
Step 4 : Join RY .
Step 5 : Now take radius more than half of RY and cneter " R " and " Y " draw two arc from both points on both side of line RY , and these arcs intersect at " A " and " B " .
Step 6 : Join line AB and that intersect line QY at " P " .
This is our required triangle PQR .
now to draw its circumcircle draw medians and for that bisect each and every side of the triangle and when median intersects we get a centroid.
measuring the point of centroid to any part of the triangle is radius and draw a cicle therefore it will be the required circumcircle
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show figure of given measures
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