Question

In triangle PQR,right angled at Q if PR=41units and PQ-QR=31,find sec²R-tan²R

Answer 1

Step-by-step explanation:

⇒PQ=5cm

⇒PR+QR=25cm

⇒PR=25−QR

Now, In △PQR

⇒(PR)

2

=PQ

2

+QR

2

⇒(25−QR)

2

=5

2

+QR

2

⇒625+QR

2

−50QR=25+QR

2

⇒50QR=600

⇒QR=12cm

⇒PR=25−12=13cm

∴sinP=

PR

QR

=

13

12

,cosP=

PR

PQ

=

13

5

,tanP=

PQ

QR

=

5

12

Hence, the answers are sinP=

13

12

,cosP=

13

5

,tanP=

5

12

.

here is your answer

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