Question

In triangle PQR , right angled at Q , PQ= 3 cm and PR= 6cm. Find sin r

Answer 1

QR = √9 + 36 = 3√5
sinR = 6/3√5 = 2/√5

Answer 2

sin r= opposite side of r / hypotenuse
Therefore sin r=3/6
sin r=1/2
And also r=30°
Hope it helps!!