Question

in triangle PQR , right angled at Q,PR + QR = 25 cm and PQ = 5 cm. determine the values of sin P, cos P and tan P.​

Answer 1

Answer:

Sin P=12/13 , tan P=12/5

Step-by-step explanation:

Let PR be 'x' and QR be = 25-x

Using Pythagorus Theorem,

==>PR^2 = PQ^2 + QR^2

x^2 = (5)^2 + (25-x)^2

x^2 = 25 + 625 + x^2 - 50x

50x = 650

x = 13

therefore, PR = 13 cm

and, QR = (25 - 13) = 12 cm

Now, Sin P = opposite/hypotenuse = QR/PR =

12/13

Tan P= opposite/adjacent = QR/PQ = 12/5

Cos P= adjacent/hypotenuse = PQ/PR = 5/13

$hope \: it \: helped \: you \: friend$

Answer 2

Answer:

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