in triangle pqr , right angled at q, pr + qr =25 cm and pq =5cm . determine the values of sinp, cos p, tan p
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Answered by
18
HEYA,
Here is your answer
First let PR be = x .Then QR becomes 25 - x.
(As PR+QR is 25).
Now apply pythagoras theoram
We get (x)2 = (25 - x)2 + (5)2 on solving we get x = 13 .
so PR = 13 and QR = 12
Now sin P = P/H =12/13 cos P
= B/H = 5/13 and
tan P = P/B = 12/5 .
Here is your answer
First let PR be = x .Then QR becomes 25 - x.
(As PR+QR is 25).
Now apply pythagoras theoram
We get (x)2 = (25 - x)2 + (5)2 on solving we get x = 13 .
so PR = 13 and QR = 12
Now sin P = P/H =12/13 cos P
= B/H = 5/13 and
tan P = P/B = 12/5 .
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7
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