Question

IN TRIANGLE PQR RIGHT ANGLED AT Q , PR+QR=8 CM AND PQ = 4 CM . DETERMINE THE VALUES OF SINP , COSP , TANP

Answer 1

Answer:

I am also searching that

Answer 2

Given, PR+QR=25 .....(i)

Also PQ=5

By Pythagoras Theorem,we get,

PR

2

=PQ

2

+QR

2

⇒PR

2

=25+QR

2

⇒PR

2

−QR

2

=25

⇒(PR+QR)(PR−QR)=25

⇒25(PR−QR)=25 .....(from (i))

⇒PR−QR=1 ......(iii)

Adding equation (i) and (iii), we get

PR+QR=25 (i)

PR−QR=1

2PR=26

⇒PR=

2

26

⇒PR=13

Therefore, QR=25−PR

=25−13

=12

sinP=

PR

QR

=

13

12

cosP=

PR

PQ

=

13

5

tanP=

PQ

QR

=

5

12