in triangle PQR right angled at Q PR + QR is equal to 25 cm and PQ is equal to 5 cm determine the values of sin p cos p and tan p
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Answered by
70
given that pr+ qr =25
25-qr=pr
pq =5
by Pythagoras theorem,
pq²+qr²=pr²
25+qr²=(25-qr)²
=25+qr²=625+qr²-50qr
=50qr=600
qr=12
therefore pq=25-12=13
therefore sin p=qr/PR
=12/13
and cos p=pq/PR
=13/5
and tan p=qr/pq
=12/13
plzz marke as brain list
25-qr=pr
pq =5
by Pythagoras theorem,
pq²+qr²=pr²
25+qr²=(25-qr)²
=25+qr²=625+qr²-50qr
=50qr=600
qr=12
therefore pq=25-12=13
therefore sin p=qr/PR
=12/13
and cos p=pq/PR
=13/5
and tan p=qr/pq
=12/13
plzz marke as brain list
Answered by
19
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