In triangle PQR s is a point on PR .PS=3,SR =4.T is a point on the side PQ .given that ST || RQ find the ratio of area of ∆PST to that of ∆PRQ
Answers
Answered by
1
please mark it as brainliest
Attachments:
enoshandashna12:
Thetheorem states that "the ratio of the areas of 2similartriangles is equal to the square of theratio of their corresponding sides
So we can appy this only for similar triangles???
*apply
yes this is only option to get answer
No we should prove triangles similar
Proof: in ∆PRQ AND ∆PST
Angle QPR=TPS COMMON ANGLES angle PRQ=PST CORRESPONDING BY AA SIMILARITY
Then we can use the ratio theorem
Anyway thank u for ur help
OK thanks for clarifying my mistake
Answered by
0
Answer:
9:49
Step-by-step explanation:
Given
ST || RQ
PS= 3 cm
SR = 4cm
Proof :--
ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²
ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²
ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49
Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49
Similar questions