Math, asked by valayasati11, 7 months ago

In triangle PQR, seg MN parallel to seg QR, and PM=15. PQ=25, PR=20, find NR

Answers

Answered by idk1233

1

Answer:

THE 2 TRIANGLES ARE SIMILAR BY AA TEST

THEREFORE,

PQ/PM= PR/NR

25/15=20/NR

5/3=20/NR

20×3=5×NR

60=5×NR

NR=60/5

NR=12

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