Question

In triangle pqr xb any point on the side qr seth x and z x b are parallel to cpr and 32 respectively and p

Answer 1

A/c to yr question,  

We know that the perimeter of pqr always be greater than the smaller pqs and psr.  

So, by keeping these point in our mind we can solve it like that,  

At first take pqr and pqs  

Then, pqr > pqs (by perimeter)  

So, pq+qr+rp>pq+qs+sp ----------(1)

Now similarly, pqr >triangle psr  

So, pq+qr+rp>sp+rp+sr--------(2)

Now, add these (1)+(2)

Then, 2pq+2qr+2rp>pq+qs+sp+sp+rp+sr

2pq-pq+2qr-(qs+sr) +2rp-rp>2sp  

Pq+qr+rp>2ps. ( Since qs+sr=qr)  

Hence, proved that pq+qr+rp>2ps..