In triangle ST=5cm QR=9cm the area of larger triangle is 50cm what is the area of shaded reigon
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Answer:
It is given that,
ST = 5 cm
QR = 9 cm
Area of ∆PQR = 50 cm²
Now, considering ∆SQR, we have
Base, QR = 9 cm
Height, ST = 5 cm
∴ Area of the ∆SQR is,
= ½ * base * height
= ½ * QR * ST
= ½ * 9 * 5
= 22.5 cm²
Thus,
The area of the given shaded region in the attached figure is given by,
= [Area of the larger ∆PQR] – [Area of the smaller ∆SQR]
= 50 cm² – 22.5 cm²
= 27.5 cm²
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