Question

sudhirs present age is 5 more thane three times the age of viru anil age is half the age of sudhir if the ratio of the sum of sudjlhir and viru age to three times anil age is 5:6 then find viru ages​

Answer 1

Answer: Viru present age = 10 year's

Step by step explanation:

Let Viru 's present age = x years

Sudhir's present age = (5 + 3x) years

Anil's present age = (5 + 3x)/2 years

▪️ Ratio of the sum of Sudhir's and Viru's age to three times Anil's age is 5 : 6 ▪️

=> (5 + 3x + x)/3(5 + 3x)/2 = 5/6

=> 2(5 + 4x)/3(5 + 3x) = 5/6

=> 12(5 + 4x) = 15(5 + 3x)

=> 4(5 + 4x) = 5(5 + 3x)

=> 20 + 16x = 25 + 15x

=> x = 5


Age of sudhir = 3x+5

=> 3 × 5 + 5
=> 20 year's




Anil = 3x+2/2

Anil = 3 × 5 + 5
=> 20/2

=> 10 year's



Hence, Viru present age is 10 year's.

Answer 2

$\bold{\huge{\underline{\underline{Answer\::-}}}}$

♦ Given

• Age of Sudhir is 5 years more than 3 times age of Viru and Anils age is half of Sudhir

• Sum of Age of Sudhir and Viru : 3 times age of Anil

= 5:6

♦ Solution

• Let The age of Viru be = x

• Then age of

>> Sudhir = 3x + 5

>> Anil = $\bold{\dfrac{3x + 5}{2}}$

• Then Sum of ages of Viru and Sudhir

= (3x + 5) + x

= 4x + 5

• Three times of Anil's age

= $3 \times \bold{\dfrac{3x + 5}{2}}$

= $\bold{\dfrac{9x + 15}{2}}$

• Then Ratio Sum of Age of Sudhir and Viru : 3 times age of Anil

$\implies$ 4x + 5 : $\bold{\dfrac{9x + 15}{2}}$ = 5 : 6

$\implies$ 2(4x + 5) : 9x + 15 = 5 : 6

$\implies$ 8x + 10 : 9x + 15 = 5 : 6

$\implies \dfrac{8x + 10}{9x + 15 } = \dfrac{5}{6}$

• By cross multiplication

$\implies (8x + 10 ) \times 6 = 5 \times (9x + 15 )$

$\implies 48x + 60 = 45x + 75$

• By organization of data

$\implies 48x - 45x = 75 - 60$

$\implies 3x = 15$

$\implies x = \dfrac{15}{3}$

$\implies x = 5$

♦ So age of Viru = 5 years

♦Then age of

>> Sudhir = 3x + 5

= 3(5) + 5

= 15 + 5

= 20 years

>> Anil = $\bold{\dfrac{3x + 5}{2}}$

= $\bold{\dfrac{3(5) + 5}{2}}$

= $\bold{\dfrac{15 + 5}{2}}$

= $\bold{\dfrac{20}{2}}$

= $\bold {10}$ years