Question

in triangle XYZ is right angled at Z, if XY = 25 cm and XYZ = 10 cm then find ZY​

Answer 1

Here at vertex Z, there is right angle

Therefore,

By pythagoras theorem

( {xy}^{2} ) = ( {xz}^{2} ) +( {zy}^{2} )(xy

2

)=(xz

2

)+(zy

2

)

Putting values,

( {13}^{2} ) = ( {12}^{2} ) + ( {zy)}^{2}(13

2

)=(12

2

)+(zy)

2

169 = 144

169 = 144 + ( {zy}^{2} )169=144+(zy

2

)

169 - 144 = ( {zy)}^{2}169−144=(zy)

2

( {zy}^{2} ) = 25(zy

2

)=25

zy = \sqrt{25}zy=

25

zy = 5cmzy=5cm

Hope it helps you

Answer 2

Answer:

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