Question

In triangle xyz.P is the point on xy and pq perpendicular xz.Xp is 4cm.Xy is 16cm.Xz is 24cm.Find xq

Answer 1

In triangle xpq and xyz

angle x=angle x(common)

angle xqp=angle xyz (90)

hence, triangle xpq similar to xyz.

so,xp/xy=xq/xz

4/16=xq/24

xq=6.

Answer 2

Answer:

Let x/a = y/b = z/c = k, [By k method]

x = ak, y= bk and z=ck

L.H.S. = a3k3/a2 + b3k3/b2 + c3k3/c2 > k3[a + b + c]

R.H.S. = [ak + bk + ck]3/[a + b + c)2 → k3[a + b + c]3/[a + b + c)2

= k3(a + b + c)

L.H.S. = R.H.S. =

Hence proved.