Question

in triangleABC ,AB=AC, AD is perpendicular to BC . Prove that AD bisects angle A and the base BC

Answer 1

Step-by-step explanation:

, in triangle ABC and triangle ACB angle ABC = angle ACB because angles opposite to equal sides are equal ab = AC and AD is common so by AAS congruence rule triangle ABC is congruent to triangle ACB

therefore by cpct CD equals to DB and angle C A D = BAD