Question

In TriangleABC, AB: BC = 1: 2, BC: AC = 3: 5 how much is AC: AB?​

Answer 1

Answer:

In a triangle ABC, AB:BC is 2:3, BC:AC is 4:5, and the perimeter is 21 cm. What are the sides?

Ans :

AC = 9 cm

BC = 7.2 cm

AB = 4.8 cm

Solution :

AB:BC = 2:3 , BC:AC =4:5 , AB +BC +AC =21

AB = 2BC/3 & BC = 4AC/5

AB = (2/3)×4AC/5

AB = 8AC / 15

2. AB + BC + AC =21

8AC/15 + 4AC/5 + AC = 21

(8 + 12 + 15)AC /15 = 21 ( upon taking L.C.M)

35AC/15 = 21

AC = 21 × (15/ 35)

AC = 9 cm

3. Upon solving,

AC = 9 cm

BC = 7.2 cm

AB = 4.8 cm