in triangleABC,ac=12cm, ab=5cm and angle bac=30° then area is
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Hey,,
In triangle ABC,
Applying Pythagoras theorem,
(AC)^2=(AB)^2+(BC)^2
144=25+BC^2
BC=13cm
Now,
Area=1/2*base*height
=1/2*12*5
=30cm^2.
Hope this helps!!
In triangle ABC,
Applying Pythagoras theorem,
(AC)^2=(AB)^2+(BC)^2
144=25+BC^2
BC=13cm
Now,
Area=1/2*base*height
=1/2*12*5
=30cm^2.
Hope this helps!!
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